Hey Grade 12 Students, your exams are near so work hard.

During beta decay electron got ejected from nucleus of atom, does this violate Heisenberg principle that tells no electron exists in nucleus.

No, beta decay does not violate the Heisenberg uncertainty principle. The Heisenberg uncertainty principle states that it is impossible to know both the position and momentum of a particle with perfect accuracy at same time. This is due to the measuring act of one property of a particle to affects the other property.

In beta decay, an electron is emitted from the nucleus of an atom. The electron is not emitted from a specific point in the nucleus, rather than from a region of space around the nucleus. Which is due to the electron's wavefunction extends into the nucleus. The uncertainty principle tells us it is impossible to know both the position and momentum of the electron with perfect accuracy. This means it is impossible to know exactly when or where the electron will be emitted from the nucleus.

The Heisenberg uncertainty principle does not violate the laws of physics. Instead, it simply tells us that there are limits to know about the behavior of subatomic particles.

Getting Info...

About the Author

A free online educational resource provider.

Post a Comment

Please do not enter any spam link in the comment box.
Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.