Hey Grade 12 Students, your exams are near so work hard.

In certain thermocouple, the thermos emf is given by E = λθ + $\frac{1}{2} $ βθ2, where θ is the temperature of hot junction, λ = 10µV(0C)-1 and β = -0.05µV(0C)-2. If the cold junction temperature is 00C. Find the neutral temperature.

Your Page Title
In a certain thermocouple, the thermoelectric emf is given by \(E = \lambda \theta + \frac{1}{2} \beta \theta^2\), where \(\theta\) is the temperature of the hot junction, \(\lambda = 10 \mu V(^{\circ}C)^{-1}\), and \(\beta = -0.05 \mu V(^{\circ}C)^{-2}\). If the cold junction temperature is \(0^{\circ}C\), find the neutral temperature.
Solution:
At Neutral temperature, Thermo-EMF us maximum.
$\frac{dE}{dθ}$ = 0
Or, λ + $\frac{1}{2}$ β.2θ = 0
Or, λ + β.θ=0
Or, θ = $\frac{- λ}{β}$
Or, θ =$\frac{-10}{-0.05}$
∴ θ = 2000C

Getting Info...

About the Author

A free online educational resource provider.

Post a Comment

Please do not enter any spam link in the comment box.
Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.