Hey Grade 12 Students, your exams are near so work hard.

To recover blue vitriol crystals from the given mixture of copper sulphate and sodium chloride | NEB Grade XII Chemistry Practical | Nepali Educate

To recover blue vitriol crystals from the given mixture of copper sulphate and sodium chloride | Nepali Educate Blue Vitriol Crystals Recovery

Experiment 01: Preparation of Decinormal Solution of Oxalic Acid

Apparatus Required

  • Pipette
  • Conical flask
  • Beakers
  • Volumetric flask
  • Funnel

Chemicals Used

Oxalic acid and Distilled water

Theory

Hydrated oxalic acid is a primary standard substance and used to prepare the primary standard solution. It is a reducing agent and gets oxidized to CO2 by losing two electrons. Its equivalent weight is \(63\).

Decinormal solution of oxalic acid contains \(1/10\)th gram equivalent of it in \(1000\)ml of solution. The weight of oxalic acid required to Prepare \(250\)ml of decinormal solution is calculated by the formula:

\[ \text{Weight required} = \left(\frac{E \times V \times X}{1000}\right) = \frac{(63 \times 250 \times 1)}{1000} \times \frac{1}{10} = 1.575\text{gm} \]

Therefore, \(1.575\) gram oxalic acid is required to prepare \(250\)ml of decinormal oxalic acid solution.

Procedure

Chemical balance was made ready for weighing. Accurately \(1.575\)gm oxalic acid was weighed and transferred into \(250\)ml of volumetric flask with the help of a funnel. The particles attached with the funnel were washed down by using water. The crystals of oxalic acid were dissolved in a minimum amount of water and then the solution was made up to the mark. Finally, the flask was covered with a lid and the solution was made homogeneous.

Observation

Weight of empty watch glass = \(W_1\)g

Weight of watch glass + oxalic acid = \((W_2 + 1.575)\)g

Weight of oxalic acid crystals = \(1.575\)g

Volume of water = \(250\)ml

Normality factor = \(\frac{\text{weight taken}}{\text{weight to be taken}} = \frac{1.575}{1.575} = 1\)

Actual normality given normality x normality factor = \(0.1 \times 1 = 0.1\)N

Result

Hence, \(250\)ml of decinormal oxalic acid solution was prepared by dissolving \(1.575\)g Oxalic acid crystals.

Conclusion

Primary standard solution can be prepared by taking the exact weight of the primary standard substance.

Precaution

  1. Weight should be taken carefully.
  2. At the end, water should be added drop by drop.
  3. Apparatus should be handled carefully.

Getting Info...

About the Author

A free online educational resource provider.

Post a Comment

Please do not enter any spam link in the comment box.
Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.